Виразити через m та n log15 1225log151225m=log35, n = log37log151225 =\( log_{15}{1225} = \frac{log_{3}{1225}}{log_{3}{15}} = \frac{2log_{3}{5}+2log_{3}{7}}{log_{3}{5}+1} = \frac{2(m+n)}{1+m}\) Related