\(10^{6lg2}-25^{1-log_{5}3}+2^{\frac{5}{ln2}}\)
\(10^{6lg2}= 2^6 = 64\)
\(25^{1-log_{5}3} = \frac{25}{25^{log_{5}3}} = \frac{25}{5^{log_{5}3^2}} = 25/9\)
\(2^{\frac{5}{ln2}} = 2^{log_{2}e^5} = e^5\)
\(64 – 25/9 + e5 = 61\frac{2}{9} + e^5 \)
Відповіді на тести