(sin(α + β ) – sinβ cos α)/ (sin(α – β ) + sinβ cos α) = (sinαcosβ + sinβ cos α – sinβ cos α) / (sinαcosβ – sinβ cos α + sinβ cos α) = sinαcosβ / sinαcosβ = 1
Відповіді на тести
(sin(α + β ) – sinβ cos α)/ (sin(α – β ) + sinβ cos α) = (sinαcosβ + sinβ cos α – sinβ cos α) / (sinαcosβ – sinβ cos α + sinβ cos α) = sinαcosβ / sinαcosβ = 1